"""
count all supersets in given range pairs
"""
import re,os
pattern = re.compile(r'(\d+)-(\d+),(\d+)-(\d+)') # return one tuple with all four numbers
# pattern = re.compile(r'(\d+)-(\d+)') # return two tuples with two numbers each

with open('./2022/4/assigned_sections.txt') as filein:
    text = filein.read()

# text = """2-4,6-8
# 2-3,4-5
# 5-7,7-9
# 2-8,3-7
# 6-6,4-6
# 2-6,4-8"""

lines = text.splitlines()

assigments = [tuple(int(e) for e in line) for line in pattern.findall(text)]

c = 0
for a0,a1,b0,b1 in assigments:
    r1, r2 = set(range(a0,a1+1)), set(range(b0,b1+1))
    if r1.issubset(r2) or r1.issuperset(r2):
        c+=1

print(c)

"""
now count all overlapping sets
"""
c=0
for a0,a1,b0,b1 in assigments:
    r1,r2 = set(range(a0,a1+1)), set(range(b0,b1+1))
    if r1.intersection(r2):
        c+=1
print(c)